Unit 1 · Topic 1.4 Beta

Estimating Limits from Tables

3 min read · freeNot practiced

A graph lets you see a limit. A table lets you test one. When you can evaluate a function but cannot see its graph, or when all you have is a set of measurements, you choose inputs closer and closer to the point and watch the outputs. This page shows how to build that table, how to read it, and how a table can fool you if you stop too soon.

Closing in from both sides

To estimate limx→af(x)\lim_{x \to a} f(x), pick inputs that approach aa from the left and from the right, getting closer each time. A standard choice is to shrink the distance by a factor of 10:

a−0.1,a−0.01,a−0.001a - 0.1, \; a - 0.01, \; a - 0.001 and a+0.001,a+0.01,a+0.1a + 0.001, \; a + 0.01, \; a + 0.1

Skip x=ax = a itself. The limit never uses it, and often the formula is undefined there anyway. Then read each side the way you read each side of a graph: the outputs for inputs below aa estimate the left-hand limit, and those above aa estimate the right-hand limit.

Worked example 1. Estimate limx→2x+2−2x−2\lim_{x \to 2} \frac{\sqrt{x + 2} - 2}{x - 2}.

At x=2x = 2 the formula has a zero denominator, so make a table:

xx1.91.991.9992.0012.012.1
f(x)f(x)0.2515820.2501560.2500160.2499840.2498440.248457

From the left, the values fall toward 0.25. From the right, they rise toward 0.25. Both sides agree, so the table suggests limx→2f(x)\lim_{x \to 2} f(x)=0.25= 0.25=14= \frac{1}{4}.

Left: the graph of f(x) = (square root of (x + 2) minus 2) over (x - 2), falling slowly, with an open circle at (2, 0.25). Right: a zoom near x = 2 showing points at x = 1.9, 1.99, 2.01 and 2.1 close to the open circle. Below: a table of x = 1.9, 1.99, 1.999, 2, 2.001, 2.01, 2.1 with f(x) = 0.251582, 0.250156, 0.250016, undefined, 0.249984, 0.249844, 0.248457.
Figure 1. The table's points on the graph. Zoomed in, they crowd around the open circle at height 0.25. LevlPrep original diagram.

The estimate is the number the values approach. The table value closest to x=2x = 2, 0.250016, is only an approximation; the limit is 0.25. On the exam, a question that says "estimate the limit" from a table expects that settled number.

When a table says "no limit"

The same three behaviors that stop a limit on a graph show up in tables:

The table showsConclusion
Left side settles on one number, right side on anotherone-sided limits differ: no limit
Outputs like 100, 10,000, 1,000,000 as xx gets closerunbounded: no limit
Outputs that keep jumping around, never settlingoscillating: no limit

Worked example 2. A shipping company charges C(w)C(w) dollars for a package of weight ww pounds. Its table gives 5.25 for ww = 1.9, 1.99, 1.999 and 2, and 7.40 for ww = 2.001, 2.01, 2.1. Find the one-sided limits at 2 and decide whether limw→2C(w)\lim_{w \to 2} C(w) exists.

limw→2−C(w)\lim_{w \to 2^-} C(w)=5.25= 5.25 and limw→2+C(w)\lim_{w \to 2^+} C(w)=7.40= 7.40 (dollars).

Since 5.25≠7.405.25 \ne 7.40, limw→2C(w)\lim_{w \to 2} C(w) does not exist. In context: the price jumps for packages just over 2 pounds.

A table suggests; it does not prove

A table checks finitely many inputs, and a function can do something surprising between them or closer in. Here is a function kk built to fool a short table:

xx1.11.011.0011.00011.00001
k(x)k(x)2.00012.00992.52.99012.9999

Stop after two columns and you would say the limit is 2. Keep going and the values head to 3. The lesson is not that tables are useless. It is that you keep going until the values clearly settle, and when the stakes are high, you confirm with algebra or a graph.

A second caution: a calculator rounds. For inputs extremely close to aa, such as a+10−12a + 10^{-12}, subtracting two nearly equal numbers can wipe out the digits that matter, and the calculator may show nonsense like 0. Inputs within 0.001 or 0.0001 of aa are usually plenty.

Tables in context

Exam tables often come from measurements: temperatures, costs, flow rates. When you state a limit in context, include the units and the direction. "As the weight approaches 2 pounds from above, the shipping cost approaches $7.40" is a complete answer. And as always, a value in the table at x=ax = a itself, such as C(2)=5.25C(2) = 5.25, tells you C(2)C(2) and nothing about the limit.

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