Unit 2 · Topic 2.6 Beta

Gravitational Force

5 min read · freeNot practiced

In 2.2 you met weight as "Earth pulls everything down with a force mg." That is a near-Earth shortcut. Here is the full story: every object with mass pulls on every other one, the pull weakens with distance in a precise way, and the reading on a scale is not the same thing as that pull.

Newton's law of universal gravitation

Two spheres of masses m1 and m2 a distance r apart, center to center, pull each other with equal and opposite forces along the line joining their centers. A panel gives |F_g| = Gm1m2/r² and how it scales: doubling r divides F by 4, tripling r divides it by 9, doubling m1 doubles it, doubling both masses multiplies it by 4.
Figure 1. Two masses pull on each other with equal forces along the line joining their centers. LevlPrep original diagram.

Any two objects with mass attract each other. The size of the force is

|Fg| = G m₁m₂ / r², with G = 6.67 × 10⁻¹¹ N·m²/kg²

Here r is the distance between the objects' centers, not the gap between their surfaces. For a planet or a sphere, treat all its mass as if it were at its center. The force always attracts, and it acts along the line joining the centers. The two objects pull on each other with forces of equal size: they are a third-law pair.

G is tiny, so the pull between everyday objects is far too small to notice. It becomes large only when one of the masses is a planet or a star.

The inverse-square form is what the exam tests most. Read it as factors:

ChangeForce becomes
Distance between centers × 2F ÷ 4
Distance × 3F ÷ 9
One mass × 2F × 2
Both masses × 2F × 4
Both masses × 2 and distance × 2F (unchanged)

Careful with "height". A space probe at a height of one Earth radius above the surface is at r = 2R from the center, so it feels a quarter of its surface weight.

The gravitational field

Divide the gravitational force on an object by the object's own mass and you get the gravitational field, g = Fg/m. It tells you how hard gravity pulls on each kilogram at that place. At the surface of a planet of mass M and radius R,

g = GM / R²

For Earth this is 9.8 N/kg. Since N/kg is the same as m/s², g is also the acceleration of any object in free fall. Near the surface, over heights that are small compared with Earth's radius, we treat g as constant; that is where Fg = mg comes from.

Worked example 1. Find the gravitational field at the surface of the Moon (M = 7.35 × 10²² kg, R = 1.74 × 10⁶ m) and the weight there of a 300 kg lander.

g = GM/R² = (6.67 × 10⁻¹¹ N·m²/kg²)(7.35 × 10²² kg) ÷ (1.74 × 10⁶ m)² = 1.6 N/kg

Fg = mg = 300 kg × 1.62 N/kg = 4.9 × 10² N. The lander's mass is still 300 kg; only the pull on it is smaller than on Earth.

Apparent weight

A 70 kg rider on a scale in an elevator, three times, with g = 9.8 m/s². Accelerating up at 1.2 m/s²: F_N, scale on rider, is longer than F_g, Earth on rider, and the scale reads 770 N. Constant velocity: equal arrows, 686 N. Accelerating down at 1.2 m/s²: F_N is shorter than F_g, 602 N. The gravitational force, 686 N, is the same in all three.
Figure 2. A rider on a scale in an elevator. The scale reads the normal force. LevlPrep original diagram.

A bathroom scale does not measure the gravitational force on you. It measures how hard it pushes up on your feet: the normal force. That reading is your apparent weight. It equals mg only when your acceleration is zero.

Worked example 2. A 50 kg student stands on a scale in an elevator that accelerates upward at 0.80 m/s². What does the scale read? Use g = 9.8 m/s².

Free-body diagram: FN (scale on student) up, Fg (Earth on student) down. Principle: Newton's second law, up positive.

FN − mg = ma, so FN = m(g + a) = 50 kg × (9.8 + 0.80) m/s² = 530 N

Earth's pull is still mg = 490 N. The scale reads more because it must both hold her up and speed her up.

The direction of the acceleration decides, not the direction of motion:

ElevatorAccelerationScale reads
Starting upward, or stopping on the way downupmore than mg
At rest or at constant velocityzeromg
Starting downward, or stopping on the way updownless than mg
Falling freely (cable cut)g, downzero: weightless

In free fall, you and the scale fall together with acceleration g, so the scale need not push at all. You feel weightless, yet gravity still acts on you fully. Astronauts in the space station are in exactly this state: at their height Earth's field is still about 90% of its surface value, and they are falling around Earth together with the station.

Two kinds of mass

Mass shows up in two different laws. In ΣF = ma it measures how hard an object is to accelerate (inertial mass). In Fg = mg it measures how strongly gravity pulls (gravitational mass). Careful experiments find the two equal. That is why a rock with 10 times the mass of a pebble feels 10 times the pull but also has 10 times the inertia, and the two fall with the same acceleration, g. The idea that gravity and acceleration are indistinguishable from the inside of a closed box is called the equivalence principle.

Common slips

Using the surface-to-surface gap or the height instead of the center-to-center distance. Forgetting to square r. Saying a heavier object falls faster. Equating a scale reading with mg in an accelerating elevator. Saying there is no gravity in orbit. And arguing from F = mg that a planet with more mass has a smaller g: g is GM/R², which grows with M.

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