Types of Chemical Bonds
Atoms bond because nuclei attract the valence electrons of neighboring atoms.
Part 1 · Hook
Why this matters
Part 2 · Before you start
What this builds on
Part 3 · Prerequisite check
Quick check before you start
1. Going across period 3 from Na to Cl, electronegativity
- increases, because the nuclear charge grows while the shell stays the same
- decreases, because the atoms get larger
- stays the same, because the atoms are in the same period
- increases, because the atoms gain more shells
Show the answer
More protons pull on electrons in the same shell, so the attraction for shared electrons grows from left to right.
- Correct: increases, because the nuclear charge grows while the shell stays the same:
- decreases, because the atoms get larger:
- stays the same, because the atoms are in the same period:
- increases, because the atoms gain more shells:
2. A magnesium atom forms an ion by
- losing its two valence electrons to become Mg²⁺
- gaining six electrons to become Mg⁶⁻
- losing one electron to become Mg⁺
- sharing its electrons to stay neutral
Show the answer
Mg has two valence electrons in the 3s subshell; losing them leaves the noble gas configuration of Ne.
- Correct: losing its two valence electrons to become Mg²⁺:
- gaining six electrons to become Mg⁶⁻:
- losing one electron to become Mg⁺:
- sharing its electrons to stay neutral:
Part 4 · See it
See it first
Part 5 · Step by step
How it works, step by step
- Two atoms come together and both nuclei attract the valence electronsthe electrons end up between the nuclei, holding the atoms together: a chemical bond
- Both atoms are nonmetals with the same electronegativitythe shared pair is attracted equally: a nonpolar covalent bond
- One nonmetal is more electronegative than the otherthe shared pair spends more time near it, giving partial charges δ− and δ+: a polar covalent bond
- A metal with a low ionization energy meets a nonmetal that attracts electrons stronglyan electron moves from the metal to the nonmetal, and the cation and anion attract: an ionic bond
- Many metal atoms each release their valence electronsthe cations sit in a sea of delocalized electrons that holds them together: metallic bonding
Part 6 · Key ideas
Key ideas
- A covalent bond is a pair of electrons shared between two atoms; both nuclei attract it.
- Unequal sharing makes a polar covalent bond: the more electronegative atom gets a partial negative charge (δ−), the other δ+.
- An ionic bond is the Coulombic attraction between a cation and an anion, usually a metal with a nonmetal.
- In metallic bonding, cations sit in a sea of delocalized valence electrons.
- Bond character is a continuum: the larger the electronegativity difference, the more polar and the more ionic the bond.
Part 7 · Misconception
A common mistake
The wrong idea: A bond is either covalent or ionic, with nothing in between.
What actually happens: Bond character changes smoothly with the electronegativity difference. Cl–Cl shares equally, H–Cl shares unequally, and Na–Cl is so unequal that the electron is effectively transferred. Use the difference, and whether a metal is involved, to place a bond along that range.
Part 8 · Check yourself
Check yourself
Exam-style questions. Anything you miss goes into your review queue.
Data table
Electronegativity values
Electronegativity values on the Pauling scale, rounded to one decimal place.
| Element | Electronegativity |
|---|---|
| H | 2.2 |
| C | 2.6 |
| N | 3.0 |
| O | 3.4 |
| F | 4.0 |
| Na | 0.9 |
| Mg | 1.3 |
| S | 2.6 |
| Cl | 3.2 |
| K | 0.8 |
| Br | 3.0 |
1. Which of these bonds is the most polar?
- C–Cl
- O–H
- N–H
- C–S
Show the answer
The electronegativity differences are O–H 3.4 − 2.2 = 1.2, N–H 0.8, C–Cl 0.6 and C–S 0.0. The largest difference gives the most unequal sharing, so O–H is the most polar.
- C–Cl: Cl is very electronegative, but so is C compared with H: the C–Cl difference is only 3.2 − 2.6 = 0.6. Polarity depends on the difference, not on one atom.
- Correct: O–H: Right: a difference of 1.2 is the largest of the four.
- N–H: The N–H difference is 3.0 − 2.2 = 0.8, smaller than the O–H difference of 1.2.
- C–S: C and S both have an electronegativity of 2.6, so this bond is the least polar of the four. Larger atoms do not make a bond more polar.
2. A bond between which two atoms has its electrons shared most equally?
- H and Br
- N and O
- H and C
- C and S
Show the answer
C and S have the same electronegativity, 2.6, so neither nucleus pulls the shared electrons harder: the bond is nonpolar covalent.
- H and Br: H and Br differ by 0.8, the largest difference of these four pairs.
- N and O: N and O differ by 3.4 − 3.0 = 0.4, so O pulls the shared electrons a little harder. Two nonmetals next to each other in a period still differ.
- H and C: H and C differ by 0.4, so the sharing is slightly unequal.
- Correct: C and S: Right: a difference of 0.0 means equal sharing.
3. In a bond between sulfur and oxygen, which atom carries the partial negative charge, and why?
- O, because its larger electronegativity pulls the shared pair toward it
- S, because it is the larger atom and holds more electrons in total
- Neither, because a bond between two nonmetals has no polarity
- S, because its lower electronegativity lets it keep more of the pair
Show the answer
O (3.4) is more electronegative than S (2.6). The shared electrons spend more time near O, so O is δ− and S is δ+.
- Correct: O, because its larger electronegativity pulls the shared pair toward it: Right: the electron density shifts toward the more electronegative atom.
- S, because it is the larger atom and holds more electrons in total: Total electron count does not decide where the shared pair sits; the pull of each nucleus on the bonding electrons does, and O pulls harder.
- Neither, because a bond between two nonmetals has no polarity: Two nonmetals share electrons, but they share them unequally unless their electronegativities match. S and O differ by 0.8.
- S, because its lower electronegativity lets it keep more of the pair: Lower electronegativity means a weaker pull on shared electrons, so S ends up with less of the electron density, not more.
Particle view
Three samples at the particle level
4. Which box best represents solid potassium chloride, KCl?
- Box 3
- Box 2
- Box 1
- Box 2 or Box 3
Show the answer
KCl is a metal with a nonmetal, so it is ionic: K⁺ cations and Cl⁻ anions held in a regular pattern, each ion next to ions of opposite charge. That is Box 1.
- Box 3: Box 3 shows separate units of two identical atoms sharing electrons, which is a covalent element such as Cl₂, not an ionic compound.
- Box 2: Box 2 shows identical metal cations among free electrons, which is a metal. KCl has no free electrons.
- Correct: Box 1: Right: alternating cations and anions.
- Box 2 or Box 3: Neither picture has both cations and anions; an ionic compound must show both kinds of ion.
5. Which box best represents a sample of solid sodium metal?
- Box 3
- Box 1
- Box 2
- Box 1 or Box 2
Show the answer
In a metal, the atoms give up their valence electrons to a shared sea, leaving cations in a regular pattern with the electrons moving among them. Box 2 shows exactly that.
- Box 3: Box 3 shows separate two-atom units of a nonmetal. Sodium atoms do not pair up into molecules.
- Box 1: Box 1 has anions as well as cations. Pure sodium has no anions, because every atom is the same element.
- Correct: Box 2: Right: metal cations in a sea of electrons.
- Box 1 or Box 2: Box 1 shows an ionic compound; only Box 2 fits a pure metal.
6. Which compound is held together by ionic bonds?
- NF₃
- CaF₂
- CS₂
- SiCl₄
Show the answer
Calcium is a metal and fluorine a nonmetal with a very different electronegativity, so Ca gives up electrons and the compound is made of Ca²⁺ and F⁻ ions.
- NF₃: N and F are both nonmetals, so they share electrons in polar covalent bonds.
- Correct: CaF₂: Right: a metal with a nonmetal.
- CS₂: C and S are both nonmetals with almost the same electronegativity; the bonds are covalent.
- SiCl₄: Si is a metalloid, not a metal, and Cl is a nonmetal; they share electrons, so SiCl₄ has polar covalent bonds.
7. Which description of the dipole arrow for an H–F bond is correct?
- The arrow points from F to H, because H gives up electron density
- The arrow points from F to H, with the crossed tail at the F end
- No arrow is drawn, because H and F are both nonmetals
- The arrow points from H to F, with the crossed tail at the H end
Show the answer
A dipole arrow points toward the more electronegative atom, where the electrons spend more time (δ−). The crossed tail, like a plus sign, sits at the δ+ end. F is far more electronegative than H.
- The arrow points from F to H, because H gives up electron density: H does give up electron density, which is exactly why the arrow points away from it, toward F.
- The arrow points from F to H, with the crossed tail at the F end: That drawing points toward H, which would mean H is δ−. F is the more electronegative atom.
- No arrow is drawn, because H and F are both nonmetals: Two different nonmetals still share unequally; H–F differs by 1.8, one of the most polar covalent bonds.
- Correct: The arrow points from H to F, with the crossed tail at the H end: Right: toward F, plus-shaped tail at H.
Part 9 · Summary
Summary
Part 10 · Up next
What comes next
Part 11 · Connections