Chapter 19 · The cardiovascular system · Topic 105

Blood pressure, flow and resistance

A&P IIFlow down gradientsInteractive lesson

Blood pressure, flow and resistance are three sides of one relationship. Your heart creates pressure, your vessels resist flow, and the difference in pressure from one end of a vessel to the other pushes blood through it. This page explains each piece with worked numbers: what the two numbers in a blood pressure reading mean, how to calculate pulse pressure and mean arterial pressure, what sets the resistance of your vessels, why pressure falls where it does along the circulation, why blood slows down in the capillaries, and how a blood pressure cuff actually measures all this.

What a blood pressure reading means

A nurse wraps a cuff around your arm and says "118 over 76". Both numbers are pressures in your large arteries, in millimeters of mercury (mm Hg): 118 mm Hg is the pressure that would push a column of mercury 118 mm high. You met pressure, and this unit, in the topic on gradients.

The pressure in your arteries is not steady. It rises and falls with every heartbeat:

Together they are your arterial blood pressure, written systolic over diastolic: 118/76.

Why diastolic pressure is not zero

During diastole the ventricle is relaxed and the aortic valve is shut, so no blood enters the aorta. Yet arterial pressure only drifts down to about 80. The reason is the elastic arteries. During ejection, the ventricle pushes in blood faster than it can drain away through the arterioles, so the aorta and its large branches stretch. During diastole, their walls recoil and keep squeezing that stored blood forward into the arterioles. Pressure falls slowly as the blood runs off, and the next beat arrives before it falls far.

Pulse pressure

Pulse pressure is the difference between the two numbers: systolic minus diastolic. It is the size of the pressure swing you feel as a pulse.

Worked example 1: pulse pressure

Problem. A patient's blood pressure is 120/80 mm Hg. What is the pulse pressure?

  1. Write the definition. Pulse pressure = systolic pressure − diastolic pressure.
  2. Substitute. Pulse pressure = 120 − 80.
  3. Calculate. 40 mm Hg.

Answer. 40 mm Hg.

Two things set the size of the swing:

Mean arterial pressure

Blood is pushed through your organs all through the cardiac cycle, not just at the peak. The pressure that matters for flow is the average pressure in your arteries over the whole cycle. This is the mean arterial pressure (MAP).

It is not simply halfway between the two numbers. At rest, each cardiac cycle spends more time in diastole than in systole. At 75 beats per minute, one cycle lasts 0.8 seconds, of which ventricular systole takes about 0.3 seconds and diastole about 0.5 seconds. So your arteries spend more of each cycle near the low number, and the average sits closer to diastolic pressure.

The usual estimate is: MAP ≈ diastolic pressure + one-third of the pulse pressure.

Worked example 2: mean arterial pressure

Problem. A patient's blood pressure is 120/80 mm Hg and her heart rate is 70 beats per minute. Estimate her mean arterial pressure.

  1. Find the pulse pressure. 120 − 80 = 40 mm Hg.
  2. Take one-third of it. 40 ÷ 3 = 13.3 mm Hg.
  3. Add it to the diastolic pressure. 80 + 13.3 = 93.3 mm Hg.
  4. Check that it is sensible. 93 lies between 80 and 120, and closer to 80, as it should at a resting heart rate.

Answer. About 93 mm Hg.

Why the one-third rule works at rest

Picture the pressure in each resting cycle as two blocks of time: pressure near the systolic value for about one-third of the cycle, and near the diastolic value for about two-thirds. The average of the whole cycle is then a weighted average, each pressure counted for the share of time it lasts:

Worked example 3: where the formula comes from

Problem. Show that a time-weighted average of 120 and 80, with 120 lasting one-third of the cycle and 80 lasting two-thirds, gives the same answer as the one-third rule.

  1. Weight each pressure by its share of time. MAP ≈ (⅓ × 120) + (⅔ × 80).
  2. Calculate each term. ⅓ × 120 = 40. ⅔ × 80 = 53.3.
  3. Add. 40 + 53.3 = 93.3 mm Hg, the same as worked example 2.
  4. Rearrange in general. MAP ≈ ⅓ × systolic + ⅔ × diastolic. Split the ⅔ × diastolic into diastolic − ⅓ × diastolic: MAP ≈ diastolic + ⅓ × (systolic − diastolic), which is diastolic + ⅓ × pulse pressure.

Answer. Both give 93.3 mm Hg: the one-third rule is a time-weighted average in disguise.

The two blocks are a simplification. A real arterial pressure wave is a quick peak followed by a long, sloping fall, and the one-third weighting is a fit that happens to match that shape at resting heart rates. It breaks down in two ways:

Automated blood pressure machines do not use the formula at all: they measure the mean directly (see measuring blood pressure, below). A mean arterial pressure of about 65 mm Hg or more is needed to push enough blood through the brain, heart and kidneys; critically ill patients are treated to keep it there.

Blood flow and the flow equation

You learned the flow equation in the topic on gradients: F = ΔP / R. Flow equals the pressure difference between the two ends of a tube divided by the tube's resistance. It applies to one blood vessel, to one organ, and to the whole systemic circuit.

For blood flow through an organ, ΔP is the pressure in the artery feeding it minus the pressure in the vein draining it. Because venous pressure is low, ΔP is close to the mean arterial pressure.

Worked example 4: flow through one muscle

Problem. The artery feeding a resting thigh muscle has a mean pressure of 93 mm Hg. The vein draining it has a pressure of 3 mm Hg. The muscle's vascular bed has a resistance of 0.9 mm Hg for each mL/min of flow. What is the blood flow through the muscle?

  1. Find the pressure difference. ΔP = 93 − 3 = 90 mm Hg.
  2. Write the equation. F = ΔP / R.
  3. Substitute. F = 90 ÷ 0.9.
  4. Calculate. F = 100 mL/min. The mm Hg cancel, leaving mL/min.

Answer. 100 mL/min.

Worked example 5: the arterioles dilate

Problem. The muscle in worked example 4 starts to work. Smooth muscle in its arterioles relaxes, and their radius increases by 19%, to 1.19 times what it was. The pressures stay the same. What is the new flow?

  1. Recall the rule. Resistance depends on 1 ÷ radius4 (Poiseuille). Length and viscosity have not changed.
  2. Raise the change in radius to the fourth power. 1.19 × 1.19 = 1.42. 1.42 × 1.42 = 2.0. So radius4 has doubled.
  3. Find the new resistance. Resistance is divided by 2: 0.9 ÷ 2 = 0.45 mm Hg for each mL/min.
  4. Use the flow equation. F = 90 ÷ 0.45 = 200 mL/min.

Answer. 200 mL/min. A 19% wider radius doubled the flow, with no change in pressure.

This is how your body sends blood where it is needed. The pressure driving flow is roughly the same for every organ, because they all draw from the same arteries. Each organ sets its own share by adjusting the radius of its own arterioles.

What sets vascular resistance

Three factors set the resistance of a vessel, just as for any tube:

Total peripheral resistance

Total peripheral resistance (TPR), also called peripheral resistance, is the resistance of the whole systemic circulation, from the aorta to the venae cavae. Most of it sits in the arterioles. You can calculate it from the flow equation.

Worked example 6: total peripheral resistance

Problem. At rest, the whole systemic circuit carries 5 L of blood per minute. Mean arterial pressure is 93 mm Hg and the pressure in the right atrium, where the circuit ends, is 3 mm Hg. What is the total peripheral resistance?

  1. Find the pressure difference across the whole circuit. ΔP = 93 − 3 = 90 mm Hg.
  2. Rearrange the flow equation for resistance. F = ΔP / R, so R = ΔP / F.
  3. Substitute. R = 90 mm Hg ÷ 5 L/min.
  4. Calculate. R = 18 mm Hg for each L/min.

Answer. 18 mm Hg·min/L.

Organs are arranged in parallel

The systemic arteries split into separate routes, one through each organ, that rejoin in the veins. Routes arranged side by side like this are in parallel, and parallel routes add up to a lower total resistance than any one of them, because blood has many paths to choose from. Two consequences follow:

Pressure along the vascular tree

Follow the pressure of blood from the aorta to the right atrium (Figure 1).

120 80 40 0 mm Hg systolic ≈ 120 diastolic ≈ 80 mean ≈ 93 steepest fall: the arterioles slow fall to near 0 aorta arteries arterioles capillaries venules veins venae cavae
Figure 1. Blood pressure along the systemic circulation. Pressure is high and pulsing in the arteries, falls most steeply across the arterioles, where resistance is greatest, and is low and steady in the veins.
  1. Aorta and large arteries. Pressure swings between about 120 and 80 with each beat. The mean falls only a few mm Hg along the large arteries, because they are wide and have little resistance.
  2. Arterioles. Pressure falls steeply, from around 85 to about 35 mm Hg. This is the biggest single drop in the circuit, because the arterioles hold the largest share of the resistance. By the rule F = ΔP / R, pushing the same flow through a large resistance uses up a large pressure difference. The pressure swings also die away here, so blood enters the capillaries at a steady pressure.
  3. Capillaries. Pressure falls from about 35 to about 15 mm Hg along their length.
  4. Venules and veins. Pressure falls slowly from about 15 mm Hg to near 0 at the right atrium. The veins are wide and have little resistance, so they need little pressure difference to carry the full flow.

That small remaining gradient, about 15 mm Hg from venules to the right atrium, drives blood back to the heart. When you lie still, it is enough on its own. When you stand, gravity opposes it in your legs, so venous return then gets important help from valves, the skeletal muscle pump and the respiratory pump. Figure 2 shows the same profile with the separate systolic, diastolic and mean lines drawn.

A graph of pressure in mm Hg against position along the systemic circulation, from the aorta through the arteries, arterioles, capillaries, venules and veins to the venae cavae. In the aorta and arteries the pressure swings with each beat between about 120 and 80, with a smooth average line near 95. The swings shrink and the pressure falls steeply through the arterioles, to about 30 at the start of the capillaries, then falls slowly to near zero at the venae cavae.
Figure 2. Systemic blood pressure along the vessels, showing systolic, diastolic and mean pressure. Pulse pressure is largest in the arteries and gone by the capillaries. OpenStax Anatomy and Physiology 2e, Figure 20.10, openstax.org, CC BY 4.0.

Flow velocity and cross-sectional area

Think of a river flowing into a wide lake. The same amount of water enters the lake each minute as flows in the river, but across the wide lake the water barely seems to move. Then it speeds up again where the lake narrows into an outlet.

Blood does the same. Two quantities are easy to confuse:

They are linked by cross-sectional area: the area of the opening that the blood flows through. Velocity = flow ÷ total cross-sectional area. When blood reaches a level of the tree with a larger total area, it slows down.

Each capillary is tiny, but you have billions of them side by side. Their total cross-sectional area is roughly a thousand times that of the aorta. So the blood slows about a thousandfold in the capillaries, then speeds up again as the veins merge into fewer, larger vessels (Figure 3).

Worked example 7: velocity in the aorta and in the capillaries

Problem. The systemic circuit carries 5 L/min. The aorta has a cross-sectional area of about 3 cm². All the systemic capillaries together have a cross-sectional area of about 3,000 cm². Find the average velocity of blood in each.

  1. Convert the flow into cm³ per second. 5 L = 5,000 mL = 5,000 cm³. 5,000 cm³ per minute ÷ 60 s = 83 cm³/s.
  2. Aorta. Velocity = flow ÷ area = 83 cm³/s ÷ 3 cm² = 28 cm/s. The cm³ ÷ cm² leaves cm.
  3. Capillaries. Velocity = 83 cm³/s ÷ 3,000 cm² = 0.028 cm/s, which is 0.28 mm/s.
  4. Compare. 28 ÷ 0.028 = 1,000. The area is 1,000 times larger, so the blood moves 1,000 times more slowly.

Answer. About 28 cm/s in the aorta and about 0.3 mm/s in the capillaries.

Total cross-sectional area (not to scale) 3 cm² about 3,000 cm² Velocity of blood about 28 cm/s about 0.3 mm/s aorta arteries arterioles capillaries venules veins venae cavae
Figure 3. Velocity is the mirror image of total cross-sectional area. Where the total area is greatest, in the capillaries, blood moves slowest; the same total flow passes every level.

The slow passage through the capillaries matters. A red blood cell spends about a second crossing a capillary, long enough for oxygen, carbon dioxide, nutrients and wastes to move between the blood and the tissue. Figure 4 puts diameter, total area, pressure and velocity side by side; notice that estimates of total capillary area differ between sources, from about 2,500 to about 4,500 cm², because the number of capillaries open at any moment varies.

Four graphs, each plotted against the sequence of vessels from elastic arteries to venae cavae. The first shows the diameter of a single vessel, largest in the elastic arteries and venae cavae and smallest in the capillaries. The second shows the total cross-sectional area of all vessels of each type, low in the arteries and veins and highest, near 4,500 square centimeters, in the capillaries. The third shows average pressure falling from about 100 to near zero, fastest across the arterioles. The fourth shows flow velocity, highest in the elastic arteries, lowest in the capillaries and rising again toward the venae cavae.
Figure 4. Vessel diameter, total cross-sectional area, average pressure and velocity along the systemic circulation. Single capillaries are the narrowest vessels, but together they have the largest total area and the slowest flow. OpenStax Anatomy and Physiology 2e, Figure 20.13, openstax.org, CC BY 4.0.

Measuring blood pressure

A sphygmomanometer (sphygmo- = pulse, mano- = thin, -meter = measure) is an inflatable cuff connected to a pressure gauge. With a stethoscope over the brachial artery, it measures arterial pressure in steps (Figure 5):

  1. Inflate the cuff above systolic pressure. The cuff squeezes the brachial artery shut at every point in the cycle. No blood passes, and you hear nothing below the cuff.
  2. Let the cuff pressure fall slowly, about 2 mm Hg per second.
  3. First tapping sound: systolic pressure. As soon as cuff pressure drops just below the peak of each wave, a spurt of blood forces through the squeezed artery at the peak of each beat. The jet of fast, swirling (turbulent) flow and the snap of the artery wall make tapping sounds, the Korotkoff sounds, named after the Russian surgeon Nikolai Korotkoff, who described them in 1905. The cuff pressure at the first sound is the systolic pressure.
  4. Sounds continue while cuff pressure lies between systolic and diastolic, because the artery opens at each peak and closes at each trough.
  5. Sounds disappear: diastolic pressure. Once cuff pressure falls below the trough of the wave, the artery stays open all the time, flow becomes smooth, and the sounds stop. The cuff pressure at the last sound is the diastolic pressure.
A graph of pressure against time. A wavy line shows the artery's pressure rising to about 120 and falling to about 80 with each beat. A straight line shows a cuff's pressure falling steadily from 130 to below 70. Below the graph, a trace of the sounds heard through a stethoscope shows no sound while cuff pressure is above the wave's peaks, tapping sounds while the cuff pressure is between the peaks and the troughs, and silence again once it drops below the troughs.
Figure 5. How a cuff reading works. The falling straight line is cuff pressure; the wave is arterial pressure. Sounds are heard only while the cuff pressure lies between the peaks and the troughs of the wave. OpenStax Anatomy and Physiology 2e, Figure 20.12, openstax.org, CC BY 4.0.

Getting an accurate reading

Most errors raise the reading. The main ones:

Worked example 8: an arm hanging below the heart

Problem. A true reading at heart level is 120/80. The patient's arm hangs so that the cuff sits 13 cm below the heart. Each centimeter of blood adds about 0.77 mm Hg of pressure. What will the cuff read?

  1. Find the extra pressure from the column of blood. 13 cm × 0.77 mm Hg per cm = 10 mm Hg.
  2. Add it to both numbers. The extra weight acts all through the cycle. 120 + 10 = 130. 80 + 10 = 90.

Answer. About 130/90, 10 mm Hg too high for both numbers.

Other methods