Carbonyl & Enolate Breadth · Section 104 of 116

Michael and Robinson

Practice this — interactive lesson

An α,β-unsaturated carbonyl has two electrophilic carbons, and which one a nucleophile picks is decided by the nucleophile rather than by the substrate. You met this with cuprates; here the nucleophile is an enolate, and the 1,4 version of the reaction has its own name.

The Michael reaction

A Michael addition is the conjugate (1,4) addition of a stabilized enolate to an α,β-unsaturated carbonyl. Two names worth keeping straight:

The donor is almost always a compound with an α hydrogen flanked by two electron-withdrawing groups: a 1,3-diketone, a β-keto ester, a malonate. Those have pKa values around 9–13 rather than 20, so an alkoxide is enough to deprotonate them completely, and the resulting enolate is stabilized enough to be soft — which is what sends it 1,4 rather than 1,2.

Recognize the product by counting. Conjugate addition joins the donor's α carbon to the acceptor's β carbon, which puts the two carbonyls 1,5 to each other. A 1,5-dicarbonyl is the Michael retron: see one, and disconnect it back to an enolate and an enone.

Compare that with an aldol, which gives a β-hydroxy carbonyl, and a Claisen, which gives a 1,3-dicarbonyl. Three condensations, three spacings — and the spacing in the product tells you which reaction made it.

Why a doubly stabilized donor

the two oxygen-bearing carbons, and the gap between themOOHAldolβ-hydroxyOOClaisen1,3OOMichael1,5Count the carbons between them and the reaction names itself — forwards to predicta product, backwards to disconnect one. A 1,5-dicarbonyl is the Michael retron.
Three condensations, three spacings. An aldol’s nucleophile hits a carbonyl carbon and the oxygen stays as an alcohol; a Claisen’s hits an ester and the alkoxide leaves; a Michael’s hits a β carbon, two positions further along, which is what pushes the two carbonyls to 1,5.Spacing survives every change of conditions, which is what makes it worth learning instead of the conditions. It is also what makes a Robinson annulation predictable: a 1,5-dicarbonyl has its ends exactly far enough apart to close a six-membered ring, so the product is a cyclohexenone without anyone having chosen the ring size.

Two reasons, and both matter in practice.

The first is control. A simple ketone enolate, made with LDA, is hard and charge-dense, so it tends to add 1,2 and gives an alcohol instead. A doubly stabilized enolate has its charge spread over two carbonyls, is softer, and adds 1,4.

The second is clean deprotonation. At pKa 9–13 the donor is fully deprotonated by a catalytic alkoxide, so you never have a strong base present that could attack the acceptor's carbonyl directly.

The Robinson annulation

Put a Michael addition and an intramolecular aldol condensation back to back and you build a ring. That is the Robinson annulation, and it is the most efficient ring-forming sequence in introductory organic chemistry.

The product is a cyclohexenone in every case you will meet. Methyl vinyl ketone is the classic acceptor, because it is cheap and its product ring is the one steroid chemistry needed.

Why six? Count it rather than assume it. An aldol joins an α carbon to a carbonyl carbon — never two carbonyl carbons — so from a 1,5-dicarbonyl the productive closure runs from the α′ carbon beyond one carbonyl to the far carbonyl carbon. Number the chain from that far carbonyl and the new bond arrives at the sixth atom. The other closures a 1,5-dicarbonyl could attempt are three- and four-membered, which is why they lose. The ring size was fixed by the spacing before the aldol had any say.

Working backwards from a cyclohexenone

The retrosynthesis runs in reverse order and is worth practicing as a drill:

Every cyclohexenone in an exam question should make you check for this. If the ring can be opened to a 1,5-dicarbonyl, a Robinson annulation made it.

What carries forward

A Michael addition is conjugate addition with an enolate donor, and it leaves a 1,5-dicarbonyl. A Robinson annulation is a Michael followed by an intramolecular aldol condensation, and it leaves a cyclohexenone. Both are recognized by product spacing rather than by memorizing conditions, which is the way to hold every condensation in this chapter.