Proton NMR is the single most informative technique in organic chemistry. Where IR identifies functional groups, ¹H NMR maps the carbon skeleton — how many distinct hydrogen environments there are, how many hydrogens are in each, and which environments sit next to which. Read together, those three pieces of information usually determine a structure outright.
What NMR measures
A hydrogen nucleus is a tiny magnet. Placed in a strong external field it can align with or against that field, and the energy gap between those two states depends on the field the nucleus actually experiences — which is the external field minus whatever its surrounding electrons shield it from. Radio waves at the matching frequency flip the nucleus, and that absorption is the signal.
The whole technique hangs on that shielding, because electron density around a nucleus varies with chemical environment. More electron density means more shielding, a smaller effective field, and a signal further upfield. Less means deshielding, and a signal further downfield.
Chemical shift: where a signal appears
Position is reported as chemical shift in parts per million, referenced against tetramethylsilane at 0. Using ppm rather than frequency makes the numbers independent of the instrument's field strength, so a shift measured on a 300 MHz machine matches one from a 600 MHz machine.
Electronegative neighbours deshield. So does an adjacent carbonyl, an adjacent pi system, and — most dramatically — an aromatic ring.
| Environment | ppm |
|---|---|
| alkyl C–H | 0.9–1.5 |
| C–H next to C=C or aryl | 1.6–2.5 |
| C–H alpha to a carbonyl | 2.0–2.5 |
| C–H next to N | 2.3–3.0 |
| C–H next to O or halogen | 3.3–4.5 |
| vinyl C–H | 4.5–6.5 |
| aromatic C–H | 6.5–8.5 |
| aldehyde C–H | 9–10 |
| carboxylic acid O–H | 10–13 |
Two entries deserve a note. Aromatic C–H sits unusually far downfield because the ring's pi electrons circulate in the applied field and generate a small field of their own that reinforces the deshielding on the outside of the ring — the ring current effect, which is specific to aromatic rings and is itself a test for aromaticity. And a carboxylic acid O–H is the most deshielded proton on the list, which is the same acidity you worked out in Module 10 showing up as a chemical shift.
Integration: how many hydrogens
The area under a signal is proportional to the number of equivalent hydrogens producing it. Only relative areas are meaningful, so integration gives you ratios — 3:2:1 — which you then scale against the molecular formula to get absolute counts.
Splitting: which environments are adjacent
A hydrogen's signal is split by non-equivalent hydrogens on adjacent carbons, because each neighbour's spin adds or subtracts a little from the local field. The result is the n + 1 rule: a hydrogen with n equivalent neighbours appears as n + 1 peaks, with relative intensities following Pascal's triangle.
No neighbours gives a singlet; one gives a doublet at 1:1; two give a triplet at 1:2:1; three give a quartet at 1:3:3:1. The spacing between the peaks of a multiplet is the coupling constant J, measured in Hz, and it is identical for both partners in a coupled pair — which is how you confirm that two multiplets are talking to each other rather than coincidentally similar.
J values carry their own structural information. In an alkene, trans coupling runs 12–18 Hz and cis coupling 6–12, which distinguishes E from Z directly. On an aromatic ring, ortho coupling is 7–10 Hz and meta coupling 2–3, which locates substituents.
1.2 ppm, 3H, triplet. Three hydrogens means a methyl; a triplet means two neighbours; 1.2 ppm means nothing electronegative nearby. The CH₃.
3.6 ppm, 2H, quartet. Two hydrogens, three neighbours, and shifted well downfield by the adjacent oxygen. The CH₂.
2–5 ppm, 1H, broad singlet. The OH — a singlet despite having neighbours, because it exchanges with other OH protons faster than coupling can register, and broad and variable in position for the same reason.
Three independent lines of evidence — shift, integration, splitting — all pointing at the same structure. That mutual agreement is what makes an assignment convincing.
Working a spectrum
A reliable order of operations. Count the signals — that is the number of distinct hydrogen environments, and a small number relative to the formula means symmetry. Read the integrations as a ratio and scale to the formula. Use the shifts to say what each environment is attached to. Use the splitting to work out what is adjacent to what. Then assemble the fragments into a structure consistent with the molecular formula and the degrees of unsaturation.
Certain patterns become recognizable with practice: a 3H triplet with a 2H quartet is an ethyl group; a 6H doublet with a 1H septet is an isopropyl; a 9H singlet is tert-butyl; and two 2H doublets in the aromatic region is a para-disubstituted ring.
Data: 1.3 ppm (3H, t), 2.0 ppm (3H, s), 4.1 ppm (2H, q). IR shows a strong peak at 1735.
DoU = (8 + 2 − 8)/2 = 1, and the 1735 IR band says that one degree is an ester carbonyl.
The triplet/quartet pair is an ethyl group, and the quartet at 4.1 puts that CH₂ on an oxygen — so it is OCH₂CH₃. The 3H singlet at 2.0 is a methyl with no neighbours, at a shift typical of alpha to a carbonyl.
Assemble: CH₃–CO–O–CH₂CH₃, ethyl acetate. Every piece of data accounted for.
What carries forward
¹H NMR is the centrepiece of every structure-determination problem, and it works best alongside the others: IR for functional groups, mass spectrometry for the formula, ¹³C for the carbon count. The next section covers the carbon experiment, which is simpler to read and answers a different question.