Alkanes & Conformations · Section 26 of 64

Conformational analysis

Practice this — interactive lesson

This section is where the chapter's parts come together into a working procedure: given a substituted cyclohexane, decide which chair it prefers and by how much — and then use that to predict what the molecule will do. The last part is the important one. Conformational analysis is not a descriptive exercise; it is how you predict which product a reaction gives.

The one-substituent rule

For a monosubstituted cyclohexane the answer is always the same: the major conformation is the chair with the substituent equatorial, because equatorial avoids the 1,3-diaxial clashes that axial cannot. The size of the preference is exactly the substituent's A-value.

Methylcyclohexane (A = 1.7) is about 95% equatorial-methyl at room temperature. tert-Butylcyclohexane (A ≈ 4.9) is over 99.9%. There is no case where a lone substituent prefers axial on steric grounds.

Multiple substituents: add the axial penalties

With two or more substituents the procedure is mechanical. Draw both chairs. For each, note which substituents are axial. Add up the A-values of the axial ones — that is that chair's penalty. The chair with the smaller total wins, and the difference between the totals is the preference.

Adding A-values is an approximation; it ignores direct interactions between two substituents that happen to be near each other, and it slightly overcounts when both axial groups are on the same face. For the comparisons you will be asked to make it is reliable, and when it is close the answer usually is close.

Worked example — trans-1,2-dimethylcyclohexane

Trans on adjacent carbons means one methyl up and one down, which puts them both axial in one chair and both equatorial in the other.

Chair A: both equatorial. Axial penalty 0. Chair B: both axial. Penalty 1.7 + 1.7 = 3.4 kcal/mol.

Chair A wins by 3.4 kcal/mol, which is better than 99:1. The trans isomer is essentially locked in the diequatorial chair.

Worked example — cis-1,2-dimethylcyclohexane

Cis on adjacent carbons means both methyls on the same face, which forces one axial and one equatorial in either chair.

Chair A: methyl 1 axial, methyl 2 equatorial. Penalty 1.7. Chair B: the reverse. Penalty 1.7.

The two chairs are equal in energy and equally populated. Neither is preferred, and the molecule is permanently carrying 1.7 kcal/mol of axial strain it cannot escape.

That is why the cis isomer is measurably less stable than the trans isomer of the same compound — about 1.7 kcal/mol less. Two compounds with identical formulas and identical connectivity, differing only in the face a methyl group sits on, with different heats of combustion.

trans-1,2-dimethylcyclohexaneCH₃CH₃both equatorialaxial penalty 0CH₃CH₃both axialaxial penalty 3.4 kcal/molLeft wins by 3.4better than 99:1 — effectively lockedcis-1,2-dimethylcyclohexaneCH₃CH₃one axial, one equatorialaxial penalty 1.7 kcal/molCH₃CH₃the same, the other way roundaxial penalty 1.7 kcal/molA dead heatequally populated — and the molecule is stuckand carries 1.7 kcal/mol it can never escape
The procedure, run twice. Draw both chairs, note which groups end up axial, add their A-values, and the smaller total wins. Trans on adjacent carbons can put both methyls equatorial in one chair, so it does, decisively. Cis cannot — one methyl is axial whichever chair it picks — so the two chairs tie, and the molecule permanently carries an axial methyl's worth of strain. That trapped 1.7 kcal/mol is measurable in the heat of combustion.Same formula, same connectivity — and the cis isomer is measurably the less stable of the two, by exactly that 1.7 kcal/mol. Two compounds differing only in which face a methyl sits on.
Worked example — when the groups are different sizes

cis-1-tert-butyl-4-methylcyclohexane. Cis on carbons 1 and 4 means one group axial and one equatorial in either chair.

Chair A: tert-butyl axial (4.9), methyl equatorial. Penalty 4.9. Chair B: methyl axial (1.7), tert-butyl equatorial. Penalty 1.7.

Chair B wins by 3.2 kcal/mol. The bulkier group takes equatorial and the smaller one absorbs the axial cost — which is the general rule whenever you cannot have everything equatorial.

cis-1-tert-butyl-4-methylcyclohexaneC(CH₃)₃CH₃tert-butyl axial, methyl equatorialaxial penalty 4.9 kcal/molC(CH₃)₃CH₃methyl axial, tert-butyl equatorialaxial penalty 1.7 kcal/molRight wins by 3.2the bulkier group takes equatorial
What to do when not everything can be equatorial. Both chairs here put something axial, so adding the A-values is the whole calculation: 4.9 against 1.7, and the chair that axialises the methyl wins by 3.2 kcal/mol. Note that the answer does not depend on liking tert-butyl — it falls straight out of the arithmetic, which is what makes this method reliable on compounds you have never seen.Cis on carbons 1 and 4 forces one group axial in either chair, so the only question is WHICH. The answer is always the same: the bulkier group takes equatorial and the smaller one absorbs the cost.
Work out cis/trans before you draw anything. Whether two substituents can both be equatorial is fixed by their cis/trans relationship and their positions on the ring, and getting that wrong invalidates everything downstream. The pattern: on 1,2 and 1,4 rings, trans allows both equatorial; on 1,3 rings, cis allows both equatorial. It flips because the axial directions alternate around the ring.
This same reasoning governs the shapes of sugars and steroids. Glucose adopts the chair that places every one of its bulky hydroxyl and hydroxymethyl groups equatorial — it is the only common hexose that can manage it, which is a large part of why glucose is the sugar life settled on. The chair-flip and A-value framework you have just learned for methylcyclohexane is exactly the framework used to analyze a steroid nucleus.

Why this connects directly to E2 elimination

E2 elimination (Module 6) carries a strict geometric requirement: the leaving group and the hydrogen being removed must be anti-periplanar, 180° apart. On a cyclohexane ring, the only way to achieve 180° between substituents on adjacent carbons is for both to be axial — one axial-up and one axial-down. Two equatorial groups are never anti-periplanar to each other, and neither is an axial/equatorial pair.

So an E2 reaction on a ring can only proceed through whichever chair places the leaving group axial, even if that chair is the minority conformation. The molecule flips into it, reacts, and is replenished by the equilibrium. Conformational analysis is literally how you predict which product forms — and sometimes whether any product forms at all.

Worked example — the classic menthyl chloride comparison

Neomenthyl chloride eliminates with ethoxide rapidly, giving mostly the more substituted (Zaitsev) alkene. Menthyl chloride, the same compound with the chlorine-bearing carbon flipped over, eliminates roughly 200 times more slowly and gives only the less substituted alkene.

The reason is entirely conformational. In neomenthyl chloride, the favoured chair already has the chlorine axial, with axial hydrogens available on both neighbouring carbons — fast, and free to give the Zaitsev product.

In menthyl chloride, the favoured chair has all three substituents equatorial, including the chlorine. To eliminate at all, the ring must flip into a strained triaxial chair, which is why it is slow. And in that chair only one neighbouring carbon has an axial hydrogen — the one that gives the less substituted alkene. Geometry overrides the usual product preference completely.

What carries forward

Conformational reasoning reappears wherever geometry gates a reaction: the anti-periplanar requirement of E2, the backside approach of SN2, the trans-diaxial opening of halonium ions and epoxides in Modules 7 and 8, and the stereochemistry of ring reactions generally. More broadly, this chapter establishes a habit worth carrying: when a reaction's outcome seems arbitrary, check whether the molecule can physically adopt the geometry the mechanism requires.