Alcohols, Ethers & Related Chemistry · Section 44 of 64

Alcohol reactions

Practice this — interactive lesson

Alcohols sit at the centre of organic synthesis. They can be made from alkenes, from carbonyls, from halides; they can be turned into halides, alkenes, ethers, esters, aldehydes, ketones and acids. Almost every synthesis route in this course passes through one. The obstacle is that an alcohol cannot react at its C–O bond until something is done about the hydroxyl group.

Why OH cannot just leave

From Module 2: a good leaving group is the conjugate base of a strong acid — stable once it has taken the electrons and departed. Hydroxide is the conjugate base of water, pKa 15.7, a very weak acid. That makes hydroxide a strong, reactive base and a terrible leaving group.

The practical consequence: an alcohol will not undergo SN1, SN2, E1 or E2 at the C–O bond under ordinary conditions. Any mechanism you draw that pushes hydroxide off a carbon is wrong. The hydroxyl must first be activated.

Two ways to activate

as it standsCOHRRRHO⁻ is the conjugate base of water,pKa 15.7 — a strong basestrong bases do not leavetwo ways to fix it1. protonate itstrong acid turns –OH into –OH₂⁺,and the group that leaves is now WATER —pKa −1.7, a weak base and a fine leaving groupcheap, but everything else has to survive the acid2. convert it to a tosylateTsCl turns –OH into –OTs, whose anion spreadsits charge over three oxygens and a ring —pKa −2.8, one of the best leaving groups there isand the C–O bond is never touched, so thestereocentre keeps its configuration
The problem with alcohols in one line: hydroxide is a strong base, and strong bases do not leave. Everything in this section is a way round that. Protonating converts the leaving group into water, which is a much weaker base; tosylation replaces it outright with an anion whose charge is spread over three oxygens. The second route has a bonus worth remembering — the C–O bond is never broken while the tosylate is made, so a stereocentre survives the conversion untouched.Both routes do the same thing: they turn a strong base into a weak one. That is the ONLY question a leaving group has to answer, and it is why alcohols need activating while alkyl halides do not.

Protonation. Under acidic conditions the oxygen is protonated first, converting OH into OH₂⁺ — now the leaving group is neutral water, conjugate base of H₃O⁺ at pKa −1.7. Seventeen pKa units of improvement from one proton. This is the route for acid-catalyzed dehydration (E1) and for ROH + HX → RX.

Sulfonate ester formation. Treating the alcohol with tosyl chloride or mesyl chloride converts OH into a tosylate or mesylate — outstanding leaving groups, being conjugate bases of very strong sulfonic acids. The reaction happens at sulfur, so the C–O bond is never broken and the configuration of any stereocenter is fully preserved through the tosylation itself. Whatever stereochemistry you get afterwards comes from the substitution step alone.

Tosylation is the method of choice when the rest of the molecule cannot tolerate strong acid, or when you want a clean, single SN2 inversion at a known stereocenter. Protonation is cheaper and simpler, but it exposes everything else in the molecule to acid and it invites carbocation chemistry with all its rearrangements.

Converting alcohols to halides

Three routes, and the choice matters.

HX directly. Tertiary alcohols react readily with HCl or HBr by SN1; primary alcohols need more forcing conditions and go by SN2. Secondary alcohols are in between and prone to rearrangement, which is the main drawback.

SOCl₂ converts ROH to RCl, and PBr₃ converts ROH to RBr. Both work under mild, non-acidic conditions, both proceed by SN2 with inversion at the carbon, and crucially neither goes through a carbocation, so neither rearranges. When a secondary alcohol needs to become a halide with its skeleton intact, these are the reagents.

Rearrangement is the standard trap. Any acid-mediated route through a carbocation can shift a hydride or methyl group before the nucleophile arrives. 3,3-Dimethylbutan-2-ol treated with HBr gives largely the rearranged tertiary bromide, not the one you would draw by swapping OH for Br. If a question specifies PBr₃ or SOCl₂, the point of the specification is usually that rearrangement has been avoided.

Dehydration: elimination of water

Under strong acid and heat — concentrated H₂SO₄ or H₃PO₄ — a protonated alcohol ionizes to a carbocation and then loses a beta hydrogen. The mechanism is E1, it follows Zaitsev's rule to give the more substituted alkene, and it carries the same rearrangement risk as any carbocation reaction.

Reactivity follows 3° > 2° > 1°, matching carbocation stability. Primary alcohols are reluctant and, when forced, proceed by a concerted E2-like pathway rather than through a primary cation.

This is the exact reverse of the acid-catalyzed hydration from Module 7, with the same intermediates in the same order. Which direction runs is a matter of conditions: dilute acid with excess water gives the alcohol, while concentrated acid with heat and the alkene distilled off as it forms gives the alkene. Le Châtelier's principle, used deliberately.

For a substrate that cannot survive strong acid, POCl₃ with pyridine effects the same dehydration under mild basic conditions by an E2 mechanism — no cation, no rearrangement.

Oxidation: a ladder, not a single step

primary alcoholOHRHHC[O]ORHCaldehyde[O]OROHCcarboxylic acidPCC stops here · Jones goes all the waysecondary alcoholOHRRHC[O]ORRCketoneone step, and that is the end of the roadtertiary alcoholOHRRRCno C–H on the carbon, so nothing to remove
Oxidation here means one thing mechanically: swapping a C–H for a C–O. So how far an alcohol can climb is settled by how many hydrogens its carbon has left. A primary alcohol has two, so it can go up twice, and choosing the reagent is how you stop it halfway. A secondary alcohol has one and takes a single step. A tertiary alcohol has none — and that is not a slow reaction, it is no reaction.

Oxidation state rises by removing C–H bonds or adding C–O bonds, and how far an alcohol can climb depends entirely on how many hydrogens sit on the carbinol carbon.

AlcoholMild (PCC, DMP, Swern)Strong (CrO₃, KMnO₄, Jones)
primaryaldehydecarboxylic acid
secondaryketoneketone
tertiaryno reactionno reaction

A primary alcohol oxidizes first to an aldehyde and then further to a carboxylic acid; stopping at the aldehyde requires a selective reagent such as PCC, Dess–Martin periodinane, or a Swern oxidation. A secondary alcohol oxidizes once, to a ketone, and can go no further because there is no C–H left on that carbon. A tertiary alcohol has no hydrogen on the carbinol carbon at all and simply does not react.

The reason strong aqueous oxidants overshoot with primary alcohols is worth knowing: the aldehyde hydrates in water to a gem-diol, which has a C–H on a carbon bearing two oxygens and is therefore oxidizable again. Remove the water — as PCC in dichloromethane does — and the overshoot stops.

Worked example — one alcohol, four products

Start with butan-2-ol and choose the reagent.

PBr₃ → 2-bromobutane, with inversion, no rearrangement.

Concentrated H₂SO₄, heat → but-2-ene, the Zaitsev alkene, by E1.

Na₂Cr₂O₇/H₂SO₄ → butan-2-one; a secondary alcohol stops at the ketone whatever the oxidant.

TsCl/pyridine then NaCN → 2-methylbutanenitrile, with clean inversion at the stereocenter.

Four transformations of one substrate, each selected by reagent. Recognizing which reagent buys which outcome is most of what synthesis planning consists of.

The other reactions

Alcohols are weak acids, pKa around 16, so a strong base such as NaH or sodium metal deprotonates them to alkoxides — better nucleophiles and stronger bases, and the starting material for the Williamson ether synthesis in the next section. Alcohols also react with carboxylic acids and their derivatives to form esters, which is Module 10's chemistry seen from the alcohol's side.

What carries forward

Alcohol activation is a reflex you will use in every multi-step synthesis from here on: you cannot do anything at that carbon until the OH becomes a leaving group. The oxidation ladder connects this chapter to the carbonyl chemistry of Modules 9 and 10 — every aldehyde and ketone you meet there can be traced back to an alcohol. And alkoxides made here are the nucleophiles of the next section.