Carboxylic Acids & Derivatives · Section 69 of 116

Acid chlorides & anhydrides

Practice this — interactive lesson

The ladder runs one way, so most syntheses starting from a carboxylic acid meet the same obstacle. A few things do run directly on the acid — Fischer esterification and LiAlH4 reduction among them — but anything that needs a reactive acylating agent does not. The fix is to climb to the top first. This is how that climb is done, and what the top of the ladder is good for once you are there.

Why the acid itself is a poor acylating agent

A carboxylic acid falls between an anhydride and an ester in reactivity, but in practice it is worse than that ranking suggests, for a reason unrelated to its carbonyl. It carries a proton at pKa 4–5, and good nucleophiles are usually also bases. An amine takes that proton instead of attacking, and the ammonium carboxylate left behind is a dead end — nucleophile protonated, electrophile now negatively charged.

Making an acid chloride

Three reagents do this, and the choice between them is practical rather than mechanistic.

Look at the by-products. Thionyl chloride and oxalyl chloride give only gases, which leave the flask as they form. That drives the reaction to completion by pulling products out of the equilibrium, and it makes the workup an evaporation rather than a separation. The phosphorus reagents leave phosphorus acids and oxychlorides behind, which must be removed — still usable, just less convenient.

SOCl2 is the reagent that turned an alcohol into an alkyl chloride back in the alcohols chapter, and it is doing the same job here. Both substrates carry an OH, a terrible leaving group; in both the sulfur converts it into a chlorosulfite, an excellent one. One reagent, one idea, two functional groups.

What an acid chloride then does

acid chlorideleaving group: Cl⁻anhydrideleaving group: RCOO⁻esterleaving group: RO⁻amideleaving group: R₂N⁻down, freelycarboxylic acidpKₐ 4–5: it protonatesthe nucleophile insteadSOCl₂the usual way upEvery step down expels a leaving group more basic than the one before it.Nothing climbs, because that would mean expelling the WORSE of the two — hence the detour.
The ranking is read straight off the leaving group: chloride, then carboxylate, then alkoxide, then amide anion, each more basic and so less willing to go than the last. Going down means the tetrahedral intermediate expels the better of the two groups it holds, which is what it does anyway; going up would mean expelling the worse one, which is why the list is one-way and why almost every route out of a carboxylic acid opens with the same move.The acid is drawn beside the ladder rather than on it because its problem is not really its position. On reactivity alone it would sit between the anhydride and the ester, but it carries a proton, and any nucleophile good enough to attack is basic enough to take that proton first. What you get is an ammonium carboxylate: the nucleophile protonated, the electrophile now anionic, and both halves of the reaction switched off by a proton transfer faster than anything else in the flask.
NucleophileProductNote
H2Ocarboxylic acidoften just moisture in the air
R'OHesterirreversible, unlike Fischer
R'NH2amide2 equivalents, or 1 plus pyridine
R'COOanhydridethe carboxylate, not the acid

The two-equivalent point in row three is a favorite exam trap. Each acylation releases one HCl, and the amine is the most basic thing in the flask, so it takes that proton and becomes an ammonium ion with no lone pair left. Half your amine is consumed as a base and only half becomes amide. A second equivalent supplies that sacrificial base; pyridine does it more economically, being basic enough to mop up HCl but too weakly nucleophilic to compete for the carbonyl.

Anhydrides

An anhydride is two acyl groups sharing one oxygen. Its leaving group is a carboxylate — resonance-stabilized, so it departs willingly, but not as willingly as chloride, whose conjugate acid is far stronger. That places anhydrides exactly where the ladder puts them: below acid chlorides, above esters. Reactive enough to acylate alcohols and amines directly, stable enough to weigh out in air.

Acetic anhydride is the standard acetylating agent. With salicylic acid it acetylates the phenol OH to give aspirin, releasing acetic acid — and that by-product is the honest cost of the method. Half the molecule is spent as a leaving group, so you buy convenience with atom economy.

Cyclic anhydrides

Heating succinic acid or phthalic acid expels water intramolecularly to give a five-membered cyclic anhydride; diacids that would have to close larger rings do not cooperate. With an amine, the ring opens at one carbonyl to give an amic acid — an amide and a carboxylic acid on the same molecule, since the departing carboxylate cannot wander off. Heating that loses water again and closes the ring to the imide, as in succinimide and phthalimide.

The other use: Friedel–Crafts

Everything above forms a carbon–heteroatom bond. The acid chloride's other major use forms a carbon–carbon bond: with AlCl3 it ionizes to an acylium ion and acylates an aromatic ring. Why that succeeds where Friedel–Crafts alkylation fails belongs to the aromatic chemistry chapter; what matters here is the link, since the SOCl2 step above is what makes an aryl ketone reachable from a carboxylic acid at all.

What carries forward

Almost every multistep problem involving a carboxylic acid opens with the same move: activate with SOCl2, then run down the ladder. Recognize it and half the planning is done before you start.